Vakra r ka square equal to a square cos2tha
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Step-by-step explanation:
Answer
Correct option is
B
(x
2
+y
2
)
2
=a
2
(x
2
−y
2
)
We have x=rcosθ,y=rsinθ
So, r
2
=x
2
+y
2
Given r
2
=a
2
cos2θ
⇒r
2
=a
2
(cos
2
θ−sin
2
θ)
⇒r
2
=a
2
(
r
2
x
2
−
r
2
y
2
)
⇒(r
2
)
2
=a
2
(x
2
−y
2
)
⇒(x
2
+y
2
)
2
=a
2
(x
2
−y
2
)
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