Chemistry, asked by vijayc2209, 8 months ago

valency factor of NH4OH​

Answers

Answered by tulasitulasi3
0

Answer:

35 g is the answer

Explanation:

equivalent weight =moleculer weight/n

where,n=acidity, for bases

n=basicity,for acids

n=valency,for elements

n=cationic charge,for compounds

equivalent weight =moleculer weight/acidity

NH4OH->NH+4+OH-

As NH4OH dissociates to give one OH- and thus it has acidity of 1

equivalent weight =35/1=35g

follow me plz

Answered by Anonymous
1

BY THIS PROCESS YOU CAN FIND THIS...

To calculate n-factor of a salt of such type, we take one mole of the reactant and find the number of mole of the element whose oxidation state is changing. This is multiplied with the oxidation state of the element in the reactant, which gives us the total oxidation state of the element in the reactant.

Similar questions