valency factor of NH4OH
Answers
Answered by
0
Answer:
35 g is the answer
Explanation:
equivalent weight =moleculer weight/n
where,n=acidity, for bases
n=basicity,for acids
n=valency,for elements
n=cationic charge,for compounds
equivalent weight =moleculer weight/acidity
NH4OH->NH+4+OH-
As NH4OH dissociates to give one OH- and thus it has acidity of 1
equivalent weight =35/1=35g
follow me plz
Answered by
1
BY THIS PROCESS YOU CAN FIND THIS...
To calculate n-factor of a salt of such type, we take one mole of the reactant and find the number of mole of the element whose oxidation state is changing. This is multiplied with the oxidation state of the element in the reactant, which gives us the total oxidation state of the element in the reactant.
Similar questions