value
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10) if a & ß are the 2 zeroes of the polynomial y^2-8y+a & a^2+ß^2=40 find the value of a
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Answer:
value of a is 12.
hope the answer is correct
explanation:
as a & B are roots
a+B=coefficient of y/coefficient of y^2
a+B=8/1=8
now (a+b)^2=(8)^2
a^2+b^2+2ab=64........(given a^2+b^2=40)
40+2ab=64a
ab=12
now product of roots =
constant term/coefficient of y^2
a×B=12=a/1
therefore a=12
Lakiah:
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