Math, asked by ramchandanikajal0998, 3 months ago

value a=1,b=2,and c=-1
2) 2a2-b2c+3abc​

Answers

Answered by tejeswarteju
14

Answer:

2a {}^{2}  - b {}^{2} c + 3abc

 = 2(1) {}^{2}  - (2) {}^{2} ( - 1) + 3(1)(2)( - 1)

 = 2 + 4 - 6

 = 6 - 6

 = 0

Answered by mss0144
2

Answer:

-8 and please follow me

Step-by-step explanation:

2a^2-b^2+3abc=2.1^2-2^2+3.1.2.-1

2-4+(-6)

-2-6

-8

Similar questions