value find of (2x-3y+4)^2
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Step-by-step explanation:
Identity we will use here :- (a+b+c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca
= (2x)^2 + (-3y)^2 + (4)^2 + 2*2x*(-3y) + 2 * (-3y) * 4 + 2*4*2x
= 4x^2 + 9y^2 + 16 -12xy -24y + 16x
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