value for k for quadratic equation 2x2-kx+k=0has equal roots is
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Answered by
2
Answer:
Hello dear...❤️
Step-by-step explanation:
ok so here it goes..!!
Value(s) of
k
for which the quadratic equation
2x^2-kx+k=0
has equal roots is...
2x2−kx+k=0
ax2+bx+c=0
a=2, b= -k
c = k
For equal roots, the discriminant must be 0
D=b^2-4ac=0
(-k)^2-4(2)k=0
k^2-8k=0
k(k-8)=0
hence, k=0,8...
hope this helps....
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Answered by
0
Answer:
this is the answer for finding value of k for quadratic equation 2x2+8x+k=o
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