Question

value of 1/√18−√32
a) √2 b) -√2 c) 1/√2 d)-1/√2
step by step answer​

Answer 1

$\frac{1}{ \sqrt{18} - \sqrt{32} } \\ \frac{1}{ \sqrt{18} - \sqrt{32} } \times \frac{ \sqrt{18} + \sqrt{32} }{ \sqrt{18} + \sqrt{32} } \\ \\ \frac{ \sqrt{18} + \sqrt{32} }{ \sqrt{18} {}^{2} - \sqrt{32} {}^{2} } \\ \\ \frac{ \sqrt{18} + \sqrt{32} }{18 - 32} \\ \\ \frac{ \sqrt{18} + \sqrt{32} }{ - 14} \\ \\ - ( \frac{ \sqrt{18} + \sqrt{32} }{14})$

In other way we can solve like this:

$1 \div \sqrt{18} - \sqrt{32} \\ 1 \div 3 \sqrt{2} - 4 \sqrt{2} \\ 1 \div (3 - 4) \sqrt{2} \\ 1 \div ( - \sqrt{2} ) \\ 1 \times \frac{1} { - \sqrt{ 2} } \\ \frac{1}{ - 1.414} \\ \\ - 0.707$