value of 16 sin 20 sin 40 sin 60 sin 80
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I will use the identity:
sin theta x sin (60-theta) x sin (60+theta) =
¼sin3 theta
In this problem theta is 20°
16 x sin theta x sin (60-theta) x sin (60+theta)x sin 60°
= 16 x ¼sin 60° x sin60°
= 4 x 3/4
= 3
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