Question

value of 25x^2 + 16y^2 + 40xy at x=1 and y=-1​

Answer 1

The value of 25x

2

+16y

2

+40xy at x=1 and y=−1 is

25(1)

2

+16(−1)

2

+40(1)(−1)

⇒25+16−40

⇒1