Value of (2x-3y)cube+(3y-4z)cube+(4z-2x)cube is
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Answer:
= 3(2x-3y)(3y-4z)(4z-2x)
Step-by-step explanation:
We know that ,
- If a + b + c = 0 ,then
- a³ + b³ + c³ = 3abc
Here ,
- a = 2x - 3y ,
- b = 3y - 4z ,
- c = 4z - 2x ,
Now ,
a + b + c = 2x-3y+3y-4z+4z-2x = 0
∴ ,(2x-3y)³+(3y-4z)³+(4z-2x)³
= 3abc
= 3(2x-3y)(3y-4z)(4z-2x)
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