Question

value of (3^-1 + 4^-1)^-1 ÷ 5^-1 is​

Answer 1

Answer:

60/7

Step-by-step explanation:

$\frac{ {( {3}^{ - 1} + {4}^{ - 1}) }^{ - 1} }{ {5}^{ - 1} } = {( \frac{ \frac{1}{3} + \frac{1}{4} }{5} )}^{ - 1}$

${( \frac{ \frac{4 + 3}{12} }{5} )}^{ - 1}$

${( \frac{ \frac{7}{12} }{5} )}^{ - 1}$

${( \frac{7}{12} \times \frac{1}{5} )}^{ - 1}$

${( \frac{7}{60} )}^{ - 1}$

$\frac{60}{7}$