Question

value of √(3-²) please solve it​

Answer 1

The value of \sqrt{3}^{-2}=\dfrac{1}{3}3−2=31

Step-by-step explanation:

We have,

\sqrt{3}^{-2}3−2

To find, the value of \sqrt{3}^{-2}=?3−2=?

∴ \sqrt{3}^{-2}3−2

=\dfrac{1}{\sqrt{3}^{2}}=321

Using the identity,

a^{-m} =\dfrac{1}{a^{m}}a−m=am1

=\dfrac{1}{\sqrt{3}\times \sqrt{3}}=3×31

=\dfrac{1}{3}=31

[ ∵ \sqrt{3} \times\sqrt{3}=33×3=3

∴The value of \sqrt{3}^{-2}=\dfrac{1}{3}3−2=31

Thus, the value of \sqrt{3}^{-2}=\dfrac{1}{3}3−2=31

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Answer 2

Answer:

3

Step-by-step explanation:

$\sqrt{3} ^{2}$ = 3