Math, asked by rakesh27, 1 year ago

value of 3 power2+8log3+logx rootx+log2 (1/16)=

Answers

Answered by abhi178

2

3^2 +8log3 +logx rootx+log2 (1/16)
=9 + 8log3 +1/2 +log2 (2)^-4
=9+8log3+1/2-4=11/2+ 8log3

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