Math, asked by scpatel0609, 12 hours ago

value of 4 cos square 60 + 3 sec square 30 - cot square 45 / cos square 60 + sin square 60​

Answers

Answered by EmperorSoul
3

we get ,

= [ 4(1/root 3 )^2 + (2/ root 3)^2 - 2 (1/ root 2)^2 ] / [ (root 3 /2 )^2 + (1/ root 2)^2 ]

solving this further , we get ,

(5/3) / (5/4)

5/3 × 4/5 = 4/3

so answer is 4/3.

hope this helps

thnx

Answered by Dalfon
39

Answer:

4

Step-by-step explanation:

(4 cos²60° + 3 sec²30° - cot²45°)/(cos²60° + sin²60°)

We know that, cos 60° = 1/2, sec 30° = 2/√3, cot 45° = 1, sin 60° = √3/2

So, for

  • cos² 60° = (1/2)² = 1/4
  • sec² 30° = (2/√3)² = 4/3
  • cot² 45° = (1)² = 1
  • sin² 60° = [(√3)/2]² = 3/4

Simply substitute the values,

→ (4 × 1/4 + 3 × 4/3 - 1)/(1/4 + 3/4)

→ (1 + 4 - 1)/[(1 + 3)/4]

→ (5 - 1)/[(4/4)]

→ 4/1

→ 4

Hence, the value of (4 cos²60° + 3 sec²30° - cot²45°)/(cos²60° + sin²60°) is 4.

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