value of 4 cos square 60 + 3 sec square 30 - cot square 45 / cos square 60 + sin square 60
Answers
Answered by
3
we get ,
= [ 4(1/root 3 )^2 + (2/ root 3)^2 - 2 (1/ root 2)^2 ] / [ (root 3 /2 )^2 + (1/ root 2)^2 ]
solving this further , we get ,
(5/3) / (5/4)
5/3 × 4/5 = 4/3
so answer is 4/3.
hope this helps
thnx
Answered by
39
Answer:
4
Step-by-step explanation:
(4 cos²60° + 3 sec²30° - cot²45°)/(cos²60° + sin²60°)
We know that, cos 60° = 1/2, sec 30° = 2/√3, cot 45° = 1, sin 60° = √3/2
So, for
- cos² 60° = (1/2)² = 1/4
- sec² 30° = (2/√3)² = 4/3
- cot² 45° = (1)² = 1
- sin² 60° = [(√3)/2]² = 3/4
Simply substitute the values,
→ (4 × 1/4 + 3 × 4/3 - 1)/(1/4 + 3/4)
→ (1 + 4 - 1)/[(1 + 3)/4]
→ (5 - 1)/[(4/4)]
→ 4/1
→ 4
Hence, the value of (4 cos²60° + 3 sec²30° - cot²45°)/(cos²60° + sin²60°) is 4.
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