Question

value of 4 cos square theta by 2 + 2 cos theta by 2 minus root 3 minus 3 =0 ..it is a quadratic equation so plz help and give value by explanation of cos theta by 2 ​

Answer 1

Answer:

Step-by-step explanation:

4cos²θ/2+2cosθ/2-√3-3=0

Let cosθ/2=x

then equation becomes

4x²+2x-√3-3=0

x=1/8[-4±√2²-4*4(-√3-3)]

=1/8[-4±√ {4-16√3+48}]

=1/8[-4±√(52-16√3]