value of (4p-3a) ^2 is
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Answer:
The answer is 16p^2 + 9a^2 - 24ap
Step-by-step explanation:
We will use (a-b)^2 = a^2 + b^2 - 2ab
a = 4p
b = 3a
a^2 = 16p^2
b^2 = 9a^2 (Because negative integers squares are positive)
2ab = 2(4p*(-3a))
= -24ap
Now we bring all terms together to get 16p^2 + 9p^2 - 24ap
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