Value of 4x-3y is divisible by 3 for : x=4, y=1 x=4, y=3 x=3, y=1 x=4, y=0
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Given equations are:
2x+3y=0(1)
4x−3y=0(2)
Now multiply (1) by (2) we get
4x+6y=0(3)
Now subtracting (2) from (3), we get
⇒9y=0
⇒y=0
now substitute the y value in (3)
⇒4x+6(0)=0
⇒4x=0
⇒x=0
⇒x+y=0+0
⇒x+y=0
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