Math, asked by aditisrivastava2869, 1 day ago

Value of (a+1)(a-1)(a^2+1) is _______​

Answers

Answered by Anonymous
2

Answer:

  • a⁴ - 1

Step-by-step explanation:

Hello!

(a + 1)(a - 1)(a² + 1) =

= (a² - 1) × (a² + 1) =

= a⁴ - 1

Success! ☺️

Answered by sudatta13
0

Step-by-step explanation:

First we will take

(a+1)(a-1)=(a^2-1) [formula (a+1)(a-1)]

Now we have the other term (a^2+1)

So again (a^2-1)(a^2+1)=(a^4-1)

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