Value of (a+1)(a-1)(a^2+1) is _______
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Answered by
2
Answer:
- a⁴ - 1
Step-by-step explanation:
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(a + 1)(a - 1)(a² + 1) =
= (a² - 1) × (a² + 1) =
= a⁴ - 1
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Answered by
0
Step-by-step explanation:
First we will take
(a+1)(a-1)=(a^2-1) [formula (a+1)(a-1)]
Now we have the other term (a^2+1)
So again (a^2-1)(a^2+1)=(a^4-1)
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