Question

Value of a^3 +b^3 when a+b=4 and ab=5

Answer 1

Step-by-step explanation:

sorry but I do not hink woo the question is correct pls do check

hope so I will

Answer 2

Answer:

63

Step-by-step explanation:

5a-b=3…………..(1) and ab=4…. ……..(2)

a-b=3…………..(1) and ab=4…. ……..(2)Squaring both side eq.(1)

a-b=3…………..(1) and ab=4…. ……..(2)Squaring both side eq.(1)a2+b^2–2ab=9

a-b=3…………..(1) and ab=4…. ……..(2)Squaring both side eq.(1)a2+b^2–2ab=9a^2+b^2–2×4=9

a-b=3…………..(1) and ab=4…. ……..(2)Squaring both side eq.(1)a2+b^2–2ab=9a^2+b^2–2×4=9a^2+b^2=17………….(3)

a-b=3…………..(1) and ab=4…. ……..(2)Squaring both side eq.(1)a2+b^2–2ab=9a^2+b^2–2×4=9a^2+b^2=17………….(3)a^3-b^3=(a-b)(a^2+b^2+ab)

a-b=3…………..(1) and ab=4…. ……..(2)Squaring both side eq.(1)a2+b^2–2ab=9a^2+b^2–2×4=9a^2+b^2=17………….(3)a^3-b^3=(a-b)(a^2+b^2+ab)= (3) ×(17 +4)

a-b=3…………..(1) and ab=4…. ……..(2)Squaring both side eq.(1)a2+b^2–2ab=9a^2+b^2–2×4=9a^2+b^2=17………….(3)a^3-b^3=(a-b)(a^2+b^2+ab)= (3) ×(17 +4)=3×21

a-b=3…………..(1) and ab=4…. ……..(2)Squaring both side eq.(1)a2+b^2–2ab=9a^2+b^2–2×4=9a^2+b^2=17………….(3)a^3-b^3=(a-b)(a^2+b^2+ab)= (3) ×(17 +4)=3×21= Hence, 63 Answer.