Question

value of A=45° and B=15°, find tanA(sinA+ B)+ cosA tan(A - B)​

Answer 1

Answer

$\frac{3+\sqrt{2} }{2\sqrt{3} }$

Step-by-step explanation:

tanA {sin (A+B)} + cosA tan (A-B)

where A = 45° and B = 15°

tan45 {sin (45+15)} + cos45 tan (45-15)

tan45{sin60} + cos45 tan30

1 · (√3/2) + (1/√2) · (1/√3)

(√3/2) + (1/√6)

(√18+2) / (2√6)

{√2 (√9+√2)} / (2√3)·√2

(√9+√2) / (2√3)

(3+√2) / (2√3)