Question

Value of a and b so that the polynomial (x^3-10x^2+ax) is exactly divisible by [x-1][x-2]

Answer 1

Step-by-step explanation:

Since (x-1)(x-2) is factor so x=1 and x=2 are solutions.

Now Let

$p(x) = x^{3} - 10 {x}^{2} + ax + b = 0$

Put x=1 and x=2 we get a+b=9 and 2a+b=32.

Solving we get a=23 and b=-14