Value of a two digits number when reversed is 6 less than twice its value when unreversed.if the difference of its digits is 2 find the number
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Given : Value of a two digits number when reversed is 6 less than twice its value when unreversed
To find : the number
Solution:
Let say two Digit number = AB
Its Value = 10A + B
When reversed number = BA
Value = 10B + A
10B + A = 2(10 A + B) - 6
=> 10B + A = 20A + 2B - 6
=> 19A = 8B + 6
B = A + 2
=> 19A = 8(A + 2) + 6
=> 19A = 8A + 16 + 6
=> 11A = 22
=> A = 2
& B = 4
Number = 24
Reversed = 42
42 = 24 * 2 - 6
24 is the number
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