Question

Value of a3 + a2b + ab2 + b3 at a = 1 and b = – 2

Answer 1

Answer:

-5

Step-by-step explanation:

$a^{3}+a^{2}b + ab^{2}+b^{3}$

= 1*1*1 + 1*1*(-2) + 1*(-2)*(-2) + (-2)*(-2)*(-2)

= 1 + (-2) + 4 + (-8)

= 1 - 2 + 4 - 8

= -5

Answer 2

Given,

Equation = $a^3 + a^2b + ab^2 + b^3$

To Find,

Value of equation at a = 1  and b = -2

Solution,

$a^3 + a^2b + ab^2 + b^3$

Putting a = 1 and b = -2 in the given equation,

Equation = $(1)^3 + (1)^2(-2) + (1)(-2)^2 + (-2)^3$

Equation = $(1) + (1)(-2) + (1)(4) + (-8)$

Equation =  $1 - 2 + 4 -8$

Equation = $5 -10$

Equation =  -5

Hence, value of the given equation at a = 1 and b = -2 is -5.