Math, asked by manvendrajput, 1 year ago

value of abc when x^a=y ; y^b =z ; z^c=x

Answers

Answered by sam12a13
0
x^a=y, x^ab=y^b(multiplying the powers with b) x^ab=z(given that v^b= z) x^abc=z^c(multiplying the powers with c) x^abc=x(given that z^c=x) x^abc=x^1, abc=1 hence proved
Hope this helps u and good luck with the answer

sam12a13: Thanks
Answered by ÒmPrAķAşhÝaDav
0
Consider xa = y
⇒ (zc)a = y  [Since zc=x]
⇒ zca = y
⇒ (yb)ca = y [Since yb = z]
⇒ ybca = y
⇒ yabc = y1
Comparing both the sides, we get
abc = 1
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