value of angle BCA in given fig please tell
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∠BAC=∠BDC (∠s in the same segment)=30° given
∠BAC+∠CBA+∠BCA=180° (∠ s of ΔABC)
30° + 110 ° + ∠BCA=180°
∠BCA = 180° - 30° - 110° = 40°
∠BCA = 40°
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