Math, asked by shivanjali14, 4 months ago

value of angle BCA in given fig please tell

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Answered by anjali983584

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∠BAC=∠BDC (∠s in the same segment)=30° given

∠BAC+∠CBA+∠BCA=180° (∠ s of ΔABC)

30° + 110 ° + ∠BCA=180°

∠BCA = 180° - 30° - 110° = 40°

∠BCA = 40°

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