Question

Value of Combination C(8,1) is​

Answer 1

$C(n, k)= \dbinom nk= \: ^nC_k=\dfrac{n!}{k!(n-k)!}$

$\implies ^8C_1=\dfrac{8!}{1!(8-1)!} = \dfrac{8!}{7!}$

$= \dfrac{8 \times 7!}{7!} = \boxed{8}$

Answer 2

Value of Combination C(8,1) is 8

Given :

The Combination C(8,1)

To find :

Value of Combination C(8,1)

Formula :

$\displaystyle \sf{C(n,r) = {}^{n}C_{r} = \frac{n!}{r! \: (n- r)!}}$

Solution :

Step 1 of 2 :

Write down the given combination

The given combination is C(8,1)

Step 2 of 2 :

Find the value of the combination

C(8,1)

$\displaystyle \sf{ = {}^{8}C_{1} }$

$\displaystyle \sf{ = \frac{8!}{1! \: (8 - 1)!} }$

$\displaystyle \sf{ = \frac{8!}{1! \: 7!} }$

$\displaystyle \sf{ = \frac{8 \times 7!}{1! \: 7!} }$

$\displaystyle \sf{ = \frac{8 }{1!} }$

$\displaystyle \sf{ = \frac{8 }{1} }$

$\displaystyle \sf{ =8 }$

Value of Combination C(8,1) is 8