Question

Value of cos 72°+ sin 18°

Answer 1

Sin(18) = Sin(90-72) = Cos(72)
2Cos(72) = 2[Cos(2*36)] = 2[$Cos^{2}$(36) - 1]
Cos(36) = $\frac{ \sqrt{5} + 1}{4}$
2($Cos^{2}$(36) - 1) = $\frac{ \sqrt{5} - 1}{2}$                                       

Answer 2

above is the ans

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