Question

Value of cos, sin and tan theta

Answer 1

Hey friend,

Here is the answer :-

sinθ = p/h

cosθ = b/h

tanθ = p/b

$\sin(0) = 0 \\ \\ \sin(30) = \frac{1}{2} \\ \\ \sin(45) = \frac{1}{ \sqrt{2} } \\ \\ \sin(60) = \frac{ \sqrt{3} }{2} \\ \\ \sin(90) = 1 \\ \\ \\ \\ \cos(0) = 1 \\ \\ \cos(30) = \frac{ \sqrt{3} }{2} \\ \\ \cos(45) = \frac{1}{ \sqrt{2} } \\ \\ \cos(60) = \frac{1}{2} \\ \\ \cos(90) = 0 \\ \\ \\ \\ \tan(0) = 0 \\ \\ \tan(30) = \frac{1}{ \sqrt{3} } \\ \\ \tan(45) = 1 \\ \\ \tan(60) = \sqrt{3} \\ \\ \tan(90) = \infty$

I hope this will help you....