Math, asked by satyamkumar532003, 3 months ago

value of - (cos theta + isin theta)^4/(sin theta+cos theta)^3​
plz solve this question

Answers

Answered by krishnamehra2906
0

Answer:

-(costheta+sintheta)×4)/sintheta+costheta×3

-4sintheta+4costheta/3sintheta+3costheta

-4(costheta+sintheta)/3(sintheta+costheta)×sintheta-costheta/sintheta-costheta

-4(costheta+sintheta)(sintheta-costheta)/3(sintheta+costheta)(sintheta-costheta)

-4(cos square theta-sin square theta)/3(sin square theta-cis square theta)

-4(1-sin square theta-sin square theta)/3(1-cos square theta-cis square theta)

-4(1-sin four theta)/3(1-cos four theta)

-4(cos four theta)/3(sin four theta)

-4(cos square theta+cos square theta)/3(cos square theta+cos square theta)

I could solve this much

sorry I couldn't solve further

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