Question

value of d/dx (cot x)

Answer 1

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Hey @cutedoll01 pls google if my answer is wrong.

Value of d(cotx) /dx = -cosec^2x.

Hope it helps

Answer 2

Answer:

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Step-by-step explanation:

⇒/dx (cot x) 

⇒d/dx [(cosx)/(sinx)] 

⇒[(cosx)'(sinx)-(cosx)(sinx)']/(sinx)²

⇒[(-sinx)(sinx)-(cosx)(cosx)]/(sinx)²

⇒[(-sin^2(x))-(cos^2(x))]/(sinx)²

⇒-[sin^2(x))+(cos^2(x))]/(sinx)²

⇒-[1]/(sinx)²

∴ the answer is -csc^2 (x)