Question

value of electric field
intensity at the surface of charged

Spherical shell?​

Answer 1

Answer:

Consider a thin spherical shell of radius R with a positive charge q distributed uniformly on the surface. As the charge is uniformly distributed, the electric field is symmetrical and directed radially outward.

(i)  Electric field outside the shell:

For point r>R; draw a spherical gaussian surface of radius r.

Using gauss law, ∮E.ds=  

q  

0

​  

 

q  

end

​  

 

​  

 

Since  

E

 is perpendicular to gaussian surface, angle betwee  

E

 is 0.

Also  

E

 being constant, can be taken out of integral.

So, E(4πr  

2

)=  

q  

0

​  

 

q

​  

 

So, E=  

4πε  

0

​  

 

1

​  

 

r  

2

 

q

​  

 

Thus electric field outside a uniformly charged spherical shell is same as if all the charge q were concentrated as a point charge at the center of the shell.

Explanation: