Value of g is constant,but when we throw a stone and a feather from a certain height,stone reach the ground fast?
horsey:
do u want the reason that y does it reaches fast isnt it?
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In vacuum both stone and feather fall on the ground from a height with the same acceleration and speed.
Let the mass of a stone by m. Let the density be d_s. So volume is m/d_s. Let d_air be the density of air.
The force acting on the stone is mg and the buoyancy force acting on the stone is m/d_s * d_air * g.
Net force downwards = m g (1 - d_air/d)
Acceleration = a_s = g (1 - d_air/d_s)
Similarly for the feather, acceleration downwards = a_f = g ( 1 - d_air/d_f)
As d_s > d_f, a_s > a_f.
The reason is buoyancy force and density.
Let the mass of a stone by m. Let the density be d_s. So volume is m/d_s. Let d_air be the density of air.
The force acting on the stone is mg and the buoyancy force acting on the stone is m/d_s * d_air * g.
Net force downwards = m g (1 - d_air/d)
Acceleration = a_s = g (1 - d_air/d_s)
Similarly for the feather, acceleration downwards = a_f = g ( 1 - d_air/d_f)
As d_s > d_f, a_s > a_f.
The reason is buoyancy force and density.
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