Value of ∆G of reversible reaction at its equilibrium is
(1) positive
(2)negative
(3)always zero
(4)may be (1)or(2).
Also explain me please
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Answered by
3
3rd option always zero.
HARI2503:
and why do you think that its 3rd iption??
because at reaction is at equilibrium
but its reversible reaction.
its not matters whethe reversible or not but given that it is in equilibrium.
okay. thank you
Answered by
4
Answer. Option (3) always zero.
From the relation, ∆G = - RTlnK.
In equilibrium, the rate of forward reaction is equal to the rate of backward reaction.
So, here, K= K forward/ K backward = 1.
Thus,putting in equation, ∆G = - RTln1 = 0 (ln1=0).
Thus, the value of ∆G at equilibrium is 0.
From the relation, ∆G = - RTlnK.
In equilibrium, the rate of forward reaction is equal to the rate of backward reaction.
So, here, K= K forward/ K backward = 1.
Thus,putting in equation, ∆G = - RTln1 = 0 (ln1=0).
Thus, the value of ∆G at equilibrium is 0.
complete answer
The answer is complete.
fine. thanks a lot for helping me.
Ur welcome.
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