Question

Value of g on the surface of the earth is 9.8 m/s2. Find its value on the surface of a planet whose mass and raadius both are two times that on earth

Answer 1

SOLUTION.

ACC to Newton

"Every body in this universe with mass attract other bodies around it with a force proportional to mass of both bodies and invertionally proportional to square of the distance"

Hence Force f is equal to....

F = GMm/r²

G is the constant

M is the mass of one body

m is the mass of other.

And we also know that

F = ma

ma = GMm/r²

a = GM/r²

a = g if M is the mass of the earth

g = GM/r²

Let the mass of the planet be M°

Radius be R°

than ACCELERATION on this planet....

a = GM°/R°²

AC to question

M° = 2M

R° = 2R

a = 2GM/(4R²)

a = GM/(2R²)

a = (GM/R²)(1/2)

a = g/2

A = 4.9m/sec²

#answerwithquality

#BAL

Answer 2

4.9 meter/second square

hope this before answer will help u lott