value of i^3+n + i^4n + i^5+n + i^6+n is
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Basic Approach : If you will solve this question with a very basic approach of finding value of (1n +2n + 3n + 4n ) and then finding its modulo value for 5, you will certainly get your answer but for the larger value of n we must got wrong answer as you will be unable to store value of (1n +2n + 3n + 4n ) properly.
Better and Proper Approach : Before proceeding to solution lets go through some of periodical properties of power of 2, 3 & 4
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