Question

Value of i(iota)-9 is
1)1
2)-1
3)i(iota)
4)-i (-iota)

Answer 1

Step-by-step explanation:

$(i) {}^{ - 9} = \frac{1}{i {}^{9} } \\ = > \: \: \: \frac{1}{i {}^{3} \times i {}^{3} \times i {}^{3} } \\ \\ = > \: \: \: \frac{1}{ - i \times - i \times \times - i} \: \: (becoz \: \: i {}^{3} = - i) \\ \\ = \frac{1}{ - i {}^{3} } \\ \\ = \frac{1}{i}=-i$