Question

Value of (i^n+i^n+1) where i =√-1 is ​

Answer 1

Answer:

Bro this question is out of my standards.

Answer 2

Step-by-step explanation:

2

n

(1+i)

2n

+

2

n

(1−i)

2n

(1+i)

2

=1+i

2

+2i=1−1+2i=2i

⟹(1+i)

2n

=2

n

i

n

⟹

2

n

(1+i)

2n

=i

n

i

−n

=

(1+i)

2n

2

n

=

(1+i)

2n

2

n

×

(1−i)

2n

(1−i)

2n

i

−n

=

(1+1)

2n

2

n

(1−i)

2n

=

2

n

(1−i)

2n

i

n

+i

−n

=

2

n

(1+i)

2n

+

2

n

(1−i)

2n