Question

value of 'k' for which (3-k)x^2 + 7 is a constant polynomial​

Answer 1

Answer:

Since it's a constant polynomial then coefficient of x^2 must be zero.

(3-k) =0

k=3

Answer 2

Step-by-step explanation:

for (3-k)x^2 + 7 to be constant polynomial

3-k=0 ( as 0*x^2+7 =7 a constant polynomial)

k=3