Question

Value of k, for which the equations 2x+3y=5 and 4x+KY =10have infinitely many solutions 18

Answer 1

Step-by-step explanation:

2x+3y=5-----1

4x+ky=10----2

4×2x+3y=5

2×4x+ky=10

__________

8x+12y=20

8x+2ky=20

-. -. -

______________

0x+10ky=0

y=0/10k

y=0

sub y=0 in eq 1

2x+3(0)=5

2x+0=5

2x=5

x=5/2