value of k for which ( x-1) is a factor of polynomial x3-kx2+11x-6
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Answered by
9
Answer:
k=-4
Step-by-step explanation:
(x-1) =0
x=1
x^3-kx^2+11x-6=0
1^3-k(1)^2+11*1-6=0
1-k+11-6=0
11-7+k=0
4+k=0
k=-4
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3
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