Question

value of k for which (x^2-kx+4) is a perfect square for all values of x is??? Plz give with explanations ​

Answer 1

Answer:

k=2 or -2

Step-by-step explanation:

$(x-2)^2$=$x^2-4x+4$

Since, k=2 is a perfect square

Thus, k=2

$(x+2)^2=x^2-(-4x+4)=x^2+4x+4$

Since, k=-2 is a perfect square

Thus, k=-2

∴, k can be 2 or -2

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Answer 2

Answer:

k=+-2

Step-by-step explanation:

(x−2)

2

=x^2-4x+4x

2

−4x+4

Since, k=2 is a perfect square

Thus, k=2

(x+2)^2=x^2-(-4x+4)=x^2+4x+4(x+2)

2

=x

2

−(−4x+4)=x

2

+4x+4

Since, k=-2 is a perfect square

Thus, k=-2

∴, k can be 2 or -2

Thank you...