value of k for which (x^2-kx-42) divisible by (x-7)is (ch-polynomials
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Answer:
Step-by-step explanation:
If x-7 is a factor ( is divisible) of x^2-kx-42
Then if we put x=7 then the above polynomial become equal to 0
So 49-7k-42=0
7-7k=0
7=7k
Hence k=1
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