Question

value of k if X + 1 is a factor of P(X) = X square + X + K is​

Answer 1

Answer: k = 0

Step-by-step explanation:

Given (x + 1) is a factor of P(x) = x² + x + k .

Suppose we assume x = -1 .

Then (x + 1) = 0 .

Since 0 is a factor of x² + x + k , we get (x² + x + k) = 0

Since we already assumed x = (-1) , we can substitute x and get :-

=> (-1)² + (-1) + k = 0

=> 1 + (-1) + k = 0

=> 0 + k = 0

=> k = 0 .

So the value of k is 0 .

Hope this helps you .

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