Question

value of k? (ii) If the roots ofr+kr+k+3 = 0 are real and equal, what is the value (D)-4 or 2 B) 6 or -2 (C) 4 or -2 (A) -6 or 2​

Answer 1

Answer:

2x

2

+kx+3=0 ---(1)

if eq (1)has equal roots then

Discriminant (1)=

b

2

−4ac

=0

b

2

=4ac

k

2

=4×2×3

k

2

=24

k=

24

=±2

6

∴ for k = ±2

16

given equation has equal roots.

solution