value of k when x=2 is a root of the quadratic equation 3x²-kx-2=0
manoj482:
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p(2)=3(2)²-k(2)-2=0
3(4)-2k-2=0
12-2k-2=0
10-2k=0
-2k=-10
k=-10/-5
k=2
3(4)-2k-2=0
12-2k-2=0
10-2k=0
-2k=-10
k=-10/-5
k=2
Answered by
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hey mate ur answer is
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hope it help u
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