Question

Value of limx → 0⁡(1+Sin(x))Cosec(x)​

Answer 1

Answer:

0 1+sinx is always 0

then cosec change into sinx which is in denominator so multiply by X on deno. n numera

so here all becomes 0

Answer 2

Answer:

0(1+Sin(x))Cosec(x)a)eb)0c)1d)∞Correct answer is option 'A'.