Question

value of log 0, log 1,log e​

Answer 1

Answer:

Let, y=log

20

1

40

⇒y=−log

20

40[∵log

1/a

b=−log

a

b]

Now 20<40<20

2

⇒log

20

20<log

20

40<log

20

20

2

⇒1<log

20

40<2[∵loga

m

=mloga,log

a

a=1]

⇒1<−y<2⇒−2<y<−1