Value of log a base a
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I'm going to say the same thing as Eric, but in a different way. let's look at something raised to a power: x^y = z x is the ...
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a^1=a.
The inverse function of y=a^x is x=log(base a) (y)
So let’s apply the log (base a).
log(base a) (a^1)=1 = log(base a)(a) = 1
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