Value of log tan x+log cos x is..
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Answered by
2
Answer:
log(sinx)
Explanation:
=log(tanx)+log(cosx)
=log(sinx/cosx)+log(cosx)
using formula log(a/b)=log(a)-log(b)
=log(sinx)-log(cosx)+log(cosx)
=log(sinx)
Answered by
2
Answer:
log(sinx)
Explanation:
here logm+logn=log(m×n)
now;
log(tanx×cosx)
log(sinx/cosx×cosx)
{we know that tanx =sinx /cosx}
log(sinx)
Hope it helps u nd mark my answer as brainlist
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