Question

Value of log2, log2,log3, 81 is
(i) 2
(ii) 3
(iii) 1
(iv) None of the above​

Answer 1

Answer:

the correct ans is option (i) 2

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Answer 2

Answer:

The answer is (i) 2

Step-by-step explanation:

logarithm, the exponent or power to which a base must be increased to yield a provided number. Expressed mathematically, x stands the logarithm of n to the base b if bx = n, in which case one writes x = logb.

Given,

$\log _{2}\left(\log _{3} 81\right)$

The concept used to solve is,

$&\log _{a} a=1$

$&\log _{a} b^{n}=n \times \log _{a} b$

Step 1

$&\Rightarrow \log _{2}\left(\log _{3} 3^{4}\right)$

$&\Rightarrow \log _{2}\left(4 \log _{3} 3\right)$

$&\Rightarrow \log _{2} 4$

Then,

$&\Rightarrow \log _{2} 2^{2}$

We get,

$&\Rightarrow 2 \log _{2} 2$

Therefore, (i) 2 is the answer.

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